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14. A Super Massive Center within the middle of our Universe
The ' Jana - Jo - Jana Theorem '

Named in honour to my niece and two very nice persons who brought me products free from testing on animals .

' Our Universe , including time , has become a little , comprehensible village ... '

Thanks a lot to that awesome team , who have created this stunning animated shortmovie !
They really have contributed to the ongoing development of fundamental research about our universe ...

Right now , we come along with the mathematical prove for the Super Massive Center of our Universe :

We are happy that we can write down about having
calculated the precise distance from the giant of a
black hole within the center of our Universe for this
first of Advent . We have to mention that we more
assume it to be a gemini system , consisting of two
objects whereas the proportion of masses might to
be within the Golden Ratio , approximately or even
exactly , the photo below illustrates this suggestion . This photo shows an assumption from the year 2019
and it might illustrate something else than the Big Bang ...

And we start ahead with exact numeric values :

The red shifted , measured frequency of this radiating source is
299.792.458.000.000.000.000.000     |   logarithm
23,476820702927927554392266208226     |   per 10
2,3476820702927927554392266208226     |   per 4,200150305 ... ( because we use the Antique Algorithm )
0,55895191833921589990318849335146     |   reciprocal value
1,789062649558922353222316702944     |   * 2
( because light intensity and hence frequency decrease by their squares )
3,5781252991178447064446334058881     |   + 23,476820702927927554392266208226

= x =

27,054946002045772260836899614114     |   10 exponent x
1.134.869.703.006.486.329.734.652.378,7289
( the original or source frequency of the Super Massive Center )

The wavelength for this frequency is
2,6416465009665214489846509174105e-19

Calculating the radius by the ' Wavelength Approach ' results :
(
18,578125299117844706444633405888
2,6416465009665214489846509174105e-9
)
3,1499735307212178634269820868621e-25   =   r   exponent   2
4.002.020.625.998.140,134841782928438   =   spin speed   ' s '
( calculated by 2 r * pi * frequency )

mass m   (   calculated by   E = m c   squared   and   E   =   h   *   f   )   =
8,3668238482914430826723074778806e-24 ;

(
' Approach C '   is used in the following calculation , we might see it here
Photon Size , Shell and Core Masses
)

- 3   *   Energy   E   (   E   =   m   *   c   squared   )   =
-2,2559178789691932977513512641967e-6 ;
( - 2c ( root of 8 ) s - 8 ( s exponent2 ) + 8 cs + 4 ( s exponent 2 ) )   =
-64.064.673.552.409.082.032.950.797.159.880 ;
m   shell   =
3,5213133133718465211706455489065e-38 ;
m   core   =
8,3668238482914078695391737594154e-24 ;
m   shell   *   m   core   *  electromagnetic Constant ' Ge '   =
6,6673899492584625898880071989189e-82
/ r   e2   =
2,1166495160141542993615324538545e-57
/ V   e2   (   ' V '   =   The speed our Universe expands with   )   =
1,3116163747726983974417956540235e-128

delta frequency
3.785,5178565115414935977221239112     |   logarithm
3,5781252991178447064446334058879
delta r
52,329935496106807848751680246907     |   logarithm
1,7187501994118964709630889372587     |   per 2
0,85937509970594823548154446862937 ;

0,85937509970594823548154446862937
+
3,5781252991178447064446334058879
-
1,7187501994118964709630889372587
-
1,7187501994118964709630889372587
=
0,9999999999999999999999999999998 =
=
' 1 ' ;

1,3116163747726983974417956540235e-128   /   ' 1 '     |   third root and exponent 2
5,5616615061089646368452592131095e-86
per target radius squared of the measured frequency
( which is 1,1502877786176224902459232075397e-28
for the measured frequency of 299.792.458.000.000.000.000.000 ,
calculated by the ' Wavelength Approach ' )
4,8350174708391530055212289140825e-58     |   1 / x
2,0682448533664607658891708333605e+57     |   per pi squared
2,0955701660526312723466250554397e+56     |   exponent 3 and fourth root of
1,7417132478203716806501293568617e+42     |   per root of [ ( 4th root of pi ) cube ]
1,7417132478203716806501293568617e+42     |   per 1,5361414298217130266275964640989
1,1338234969826428288348939717868e+42
meters of distance of the Super Massive Center of our Universe from Earth

...

The Antique Algorithm results   exponent   4,200150305 ...
what we have found out by calculating   ' G '   .
The Energy which arrives on our Earth from   HD   1
is a very bright   UV   Light and we are going to use a
frequency of ten exponent   ( e )   15,5   which is just
the average value of   UV   Light , because I cannot get
' bright UV ' , what we assume to be the measured

10 e15,5 = 1     |   logarithm
15,5 = 10 e0     |   per 10
or just 1,5 = ( 10 / 10 ) exponent 0
1,55 = 1 ;

1,55
/
4,2001503
=
0,36903441288755785715573083182285     |   1 / x
2,7097743870967741935483870967742     |   times 2
( because we need a square due to light intensity and hence
frequency also are getting less inverted by their squares )

5,4195487741935483870967741935484     |   plus 15,5
=
20,919548774193548387096774193548 ;

10 exponent 20,91954877419 ... spins per second
should be the maximum of the radiation spectrum of source
or original energy within the Center of the Galaxy HD 1 .

We have targeted the most likely Energy Value by the
Antique Method which has been refined yesterday , too ...

We strongly assume the center of our Universe to
consist of a super large ' Monster ' of a Black Hole ,
the ' point of origin ' of the Big Bang , which should
expand at times , and massing again ...

The maximum of cosmic radiation with a frequency
of 2,99792458 * 10 to the power of 23 spins per
second might show us the way to calculate the high
energies in this megalomaniac mass concentration .
We set ~ 3 * 10 exponent ( e ) 23 equal to 1 unit
of Energy E , while E should to be proportional to
the frequency we calculate with .
We just might calculate with the measured frequency
and 10 exponent ~ 4,2001503 ... ( Antique Algorithm )
resulting the original frequency of the radiating source ,
what
results the ( source or original ) energy of this
mega massive black hole in the center of our
Universe or better the middle of our existence of
the four dimensions , including space and time .
Knowing this most likely ' target Energy ' and the
radius of photons at 3 * 10 e23 spins per second
( wich is the red shifted result of the energy emitted
from the mega massive black hole )
we could calculate the distance to the ' Big Bang ' ...

The Antique Approach should work out well , the single
exception might to be the core of our Milky Way , which
is a Galaxy also , but our Earth is within this Galaxy ...

If we would calculate the distance from the core of our
Milky Way , we would just go ahead with :
A measured frequency of 10 exponent 20, 5
The logarithm is 20 , 5     |   per 10
2 , 05     |   per 4,200150305 ...
0,48807777130252008921856904832838     |   1 / x
2,0488538073170731707317073170732     |   per 2
1,0244269036585365853658536585366 ;
1,0244269036585365853658536585366
plus 20 , 5
=
21,524426903658536585365853658537 ,
the exponent of 10 for the most likely target radiation ;

We have found to the final conclusion
for using either the squareroot ( logarithm per two )
or just a square ( logarithm times two ) for calculating
the distance of radiating centers ...
The Apex should to be the most likely maximum
of the radiating source by the ' Antique Algorithm ' :
10 exponent 4, 200150305 ...     |   squareroot
results
10 exponent 2,1000751525
and if we see the reciprocal value of the logarithm for the source below this value
(
like e . g . 2,0488538073170731707317073170732 ,
used for measuring the Energy of the Center of our Milky Way
)
we are going extract the squareroot , and if the measured value is
above 2,1000751525
(
like e . g . 2,7097743903225806451612903225806 which should to be squared
and added to the exponent 15 , 5 for the Galaxy HD 1
)
we will simply square ...

We might like to add another issue , which we have forgotten
to mention up to date
'
Calculating the red shift distance for e . g . gamma particles to photons at one
spin per second we have to remind , that force of attraction within the one spin
particle system is higher than ' 1 ' while the electromagnetic force within e . g .
gamma particles is smaller than ' 1 ' , calculated by Ge * masses per radius
exponent two , and hence we have to invert this value of ' E '
while ' inverting ' also means ' to multiply ' with the target photon radius , not
dividing like for Energy values smaller than ' 1 ' when solving the equivalent ...
'

In the following calculation , we go ahead with
the mass of our Universe , 10 e50 kilogramms ,
the Super Massive Center owning 10 e 50 kg ,
the distance to the Super Massive Center from
our Earth , 10 e 42 meters , the Gravitation
Constant G as 10 e -11 , and the existing
way to calculate motion of two ' celestial objects '
nearing or floating of each other ,

'
Force of Attraction of two celestial bodies
( referred to as ' F ' )
per
Speed our Universe expands with
( referred to as ' V ' )

*

either ( for two objects drifting apart )
{
1 / root of ( F / V )
per pi squared
per
approximately 1,86 ...
( whereas ' 1,86 ... ' poses the ratio of kilogramm per meter ,
what we have found out by calculating with the speed our Moon
leaves the orbit of Earth , and we are going to precise this value :
By our research work about photon particles , we
have seen that delta radius exponent 3 is equal
to delta frequency exponent 2 and that delta mass
of the spinning particle gemini systems is directly
proportional to delta frequency .

Delta radius of a 400 nm wavelength photon and
a 700 nm wavelength photon is
1,4521964333909260217517351196628     |   third root
1,1324224101120438655491213255449     |   squareroot
1,0641533771557762930093370704405 ;

1,0641533771557762930093370704405
times delta mass ( 1, 75 ) is equal to
1,862268410022608512766339873271

And this value should pose the exact ratio of
kilogramms per metres ...
We are going to let flow this value into our
current calculations ...
)
}

or ( used for two objects nearing )
{
1 / ( F / V ) squared
per root of pi
per
approximately 1,86 ...
}

is equal to

the speed of two celestial objects
nearing or floating off each other
;
'

So we have
10 e 50 * 10 e 50 * 10 e - 11
per
( 10 e 42 square )
what results
10 e 5 ;

10 e 5
per
V ( rounded to 10 e 35 )
results
10 e -30 ; v
Because we are right here ,
in the Entity of our Universe
( and not in Subdivisions ) ,
we will have the reciprocal
value of 10 e - 30
what is 10 e 30 ;

1 / [ ( root of ( 10 e 30 ) ]
=
10 e - 15
;

10 e 30
times
10 e - 15

results 10 exponent 15 meters per second ,
what poses the speed the shell , our Universe ,
all the Galaxies except for the Super Massive
Center , float off from this Center due to the
speed our Universe expands with ...

This is superluminal for sure , and since we know
that superluminal motion curves space like magnetism ,
we might see that the radiation from the Super Massive
Center is going to reach us from almost any direction within
the bent cosmos and that the Entity of our Universe behaves
a little like a photon as a spinning particle gemini system ... Both the superluminal expansion speed of our Universe , and
the natural space curvature should to be responsible for the
intensity of radiation from the Super Massive Center ( SMC ) ,
its distribution arriving on Earth , and the Cosmic Microwave
Background Cold Spot ...

All the former work which has led to this new
understanding is going to be written below ,
in order to preserve clarity :

We might have found to a solution for calculating the
distance of two Galaxies by the ' Antique Algorithm ' .

The measured radiation spectrum , its Energy ( and
its maximum ) which arrives on Earth is referred to as
' spectrum ' within the following calculation :

( spectrum ) to the power of four
times
fifth root of ( spectrum )
times
2048 th root of { fifth root of ( spectrum ) }
times
8192 th root of { fifth root of ( spectrum ) }
times
16384 th root of { fifth root of ( spectrum ) }
( and so on )
...
should be equal to the original radiation spectrum , which can
be measured in the very near or in the core of the Galaxy ...

It should work out well , because we target the most likely
ratio ' Amount of Energy per distance ' of electromagnetic
particles , whereas Energy gets less because the photons
are passing a vacuum which is not perfect and electromagnetic
attraction should do the other part of photons loosing energy ...

We are going to write down the work about ' Calculating a Red Shift
over a certain distance within our Universe ' in order to maintain
clarity within this new and concluded work of science :

E ( of attraction ) might to be directly proportional
to frequency and hence to the Energy photons hold .
frequency squared = E squared = radius exponent 3
(
for a simplification we have left away
'
frequency squared
/
10 exponent
{
exponent of ten from ( root of [ delta r ] ) plus
exponent of ten from ( delta f ) minus
exponent of ten from ( delta r ) minus
exponent of ten from ( delta r )
}
'
)
3rd root of ( delta E squared ) = delta radius r
E = ( 1 / d ) squared
( because Light Intensity gets less with its inverse square )
3rd root of { [ ( 1 / d ) squared ] squared } = delta E as distance d exponent 4
So we have
delta radius r = ( target ) r squared / delta E as distance d exponent 4 ;
what should be
( root of ) delta E = ( root of ) delta E ;

3rd root of

{

( E squared )
per
(
10 exponent
{
exponent of ten from ( root of [ delta r ] ) plus
exponent of ten from ( delta f ) minus
exponent of ten from ( delta r ) minus
exponent of ten from ( delta r )
}
)
squared

(
because
=
root of ( delta r ) * delta frequency f
/
10 exponent
{
exponent of ten from ( root of [ delta r ] ) plus
exponent of ten from ( delta f ) minus
exponent of ten from ( delta r ) minus
exponent of ten from ( delta r )
}
)

}

=

target radius ( r ) squared
* pi squared
( because we calculate with 1 / 2 spin )

/

(
third root of ( distanced ( d ) exponent 4 )
* root of [ ( 4th root of pi ) cube ]
( because we calculate with 1 / 2 spin )
)

Let us see an example with the Galaxy HD 1 ,
which is about 13,5 * 10 exponent 9 light years
away from our Earth , and we assume it to having
owned a high gamma ray emission like Milky Way .
These gamma particles should have turned into an
ultraviolet radiation by passing the high distance :
Gamma particles own a radius of
1,5776837846509109336632597026682e-17
while ultraviolet ' C ' light particles own a radius of
1,0725146985555128000387220504706e-19 ;
the delta of both the radii is
147,10136716781330394542515197408     |   root
12,128535244118034220613228235627
and the delta frequency is
10 exponent 5,5 ;
147,10136716781330394542515197408     |   logarithm
2,1676167091019553818829105705697
12,128535244118034220613228235627     |   logarithm
1,0838083545509776909414552852849 ;
1,0838083545509776909414552852849
plus 5,5
6,5838083545509776909414552852849
minus
2,1676167091019553818829105705697 * 2
=
2,2485749363470669271756341441455 I * 2
4,497149872694133854351268288291 = x     |   10 exponent x
31.415,926535897932384626433832802 ;

3,162277660168379331998893544434e+115
(
what is ( approximately ) equal to E ,
calculated by
E = f / V
while
force of Attraction of Matter and Antimatter
( referred to as ' f ' )
/
( Speed our Universe expands with ) squared
( referred to as ' V ' squared )
)
/
31.415,926535897932384626433832802
=
1,0065842420897407007245506028551e+111     |   third root and square
1,0043846918524871426914865729229e+74     |   per [ 1 / ( target radius uv light ) squared ]
1,0043846918524871426914865729229e+74     |   per [ 8,6934766985159719506014419504062e+37 ]
=
1,1553314360685427136869763562705e+36     |   per pi squared
1,1705954860166663676011936370977e+35     |   exponent 3 and 4th root of
200.126.745.943.034.360.211.228.135,5171     |   per root of [ ( 4th root of pi ) cube ]
200.126.745.943.034.360.211.228.135,5171     |   per root of [ 1,5361414298217130266275964640989 ]
130.278.854.575.428.893.215.844.623,86535
in comparison to
127.723.500.000.000.000.000.000.000
( 13,5 * 10 exponent 9 * 9,461 * 10 exponent 15 meters )

We are happy to announce that we were able
to find a way for calculating the frequency of
spins per second our Milky Way turns around
the Super Massive Center of our Universe .
Knowing frequency and distance ( radius ) ,
we can calculate speed and by knowing the
exact value for G we can calculate the mass
of our Milky Way and mass of the big ' Bright
Dark Center ' ...

Our Equivalent for calculating frequency of Milky
Way spinning around the Dark Center is going to
be like the following ( it works in a similar manner
to the equivalent for photons as electromagnetic
particles , the slight difference is a square , the
equivalent for photons can be seen online , here
Photon Size , Shell and Core Masses
)

( delta frequency )
( frequency of Milky Way around the Center of our Universe
per frequency of e.g. our Sun around the Center of Milky Way )
squared

per

(
10 exponent
{
[ logarithm ( root of delta radius ) ]
plus
logarithm ( delta frequency )
minus
[ logarithm ( delta radius ) ]
minus
[ logarithm ( delta radius ) ]
]
)
squared

=

( distance of our Milky Way to the Super Massive Center to the power of three )

We would like to give an example using
our Moon turning around Earth and our
Earth turning around Sun :

Moon frequency =
4,2362203208709831650571062833111e-7 ;
Earth frequency =
3,168756727904284686377246116169e-8 ;
Delta frequency =
13,368714245453247784727890285011     |   square
178,72252057658460025761831415842 ;
Moon ' radius ' ( = distance of Moon from Earth ) =
384.400.000 meters ;
149.600.000.000 meters ;
Delta radius = 389,17793964620187304890738813736     |   exponent 3
58.944.683,971400902843128602189989 ;

logarithm ( log ) 389,17793964620187304890738813736 =
2,590148214531934805170700560059     |   per two ( because we use the square root of the delta radius )
1,2950741072659674025853502800295     |   plus log ( delta frequency )
1,2950741072659674025853502800295 + 1,1260896403991471367773464154491
2,4211637476651145393626966954786     |   minus log ( delta radius ) =
-0,16898446686682026580800386458045     |   minus log ( delta radius ) =
-2,7591326813987550709787044246395 = x I 10 exponent x
0,0017412748148851844505944797205     |   square
3,0320379809534333759127412410551e-6

( Delta frequency ) squared
per 3,0320379809534333759127412413368e-6
58.944.683,971400902843128602189999

We might hope for no shift of this equivalent by these ' large ' dimensions like there is a relative effect
for photons at light speed ... And glad we are to see a shift of duration of time by the large mass , because
otherwise , the radiation from this Bright Center would need about 10 exponent 26 years until reaching our Earth ,
calculated by this certain distance ...

Happy we are , that we can write down these lines !
We have calculated the Mass of the Super Massive
Center of our Universe to
1,8629952550872468333656374107205e+50
kilogramms
and we are going to see the calculation by the following :

Solving the equivalent written above for delta frequency
results

logarithm ( log ) delta frequency ( f )
=
3 * log [ delta radius ( r ) ]
+
log [ root of ( delta r ) ]
-
2 * log ( delta r )
;

And we are going to see exact numeric values for now :
radius of Moon around Earth =
384.400.000 meters ;
radius of Milky Way around the Super Massive Center =
1,1338234969826428288348939717868e+42 ;
delta r =
2,9495928641588002831292767216098e+33     |   log
33,469762073926712980705194163186     |   per two [ logarithm of ( root of delta r ) ]
16,734881036963356490352597081593
33,469762073926712980705194163186     |   times two
66,939524147853425961410388326372

33,469762073926712980705194163186 * 3 =
100,40928622178013894211558248956     |   plus
16,734881036963356490352597081593 =
117,14416725874349543246817957115 I minus
66,939524147853425961410388326372
50,204643110890069471057791244779 = x     |   10 exponent x
1,6019284368513716925909748738909e+50     |   reciprocal value
6,2424761118887663884771273958825e-51 = delta frequency ;
delta frequency = frequency of Milky Way per frequency of Moon ;
frequency of our Moon = 4,2362203208709831650571062833111e-7 ;
6,2424761118887663884771273958825e-51
per
4,2362203208709831650571062833111e-7
1,4735957148246929066155197927828e-44     |   reciprocal value
6,7861217967708702841504717399495e+43
( = seconds for one complete spin )

Now we will see calculating mass by
mass ( m ) = ( r exponent 3 * 4 * pi exponent 2 ) / [ G * ( 1 spin in seconds ) squared ] ;

m
=
5,7543476388147843394193998598772e+127
/
6,7071967560044286090261498912392e-11
/
4,6051449040608704890918700231293e+87
=
1,8629952550872468333656374107205e+50
kilogramms ;

During the springtime of the year 2023 we have found , that
we have to correct our calculation for the determination of the
mass of the Super Massive Center ( SMC ) .
And this result for mass of the SMC mentioned above is valid
for a rough estimation .
An interesting thing we have recognized is , that the
equation to calculate the delta radius by the delta of
frequency , results true expressions for each pairs of
values we are going to use :

( delta frequency ) squared
per
(
10 exponent
{
T ( 1 ) * 2
}
)
=
;

T ( 1 ) =
{
[ logarithm ( root of delta radius ) ]
plus
logarithm ( delta frequency )
minus
[ logarithm ( delta radius ) ]
minus
[ logarithm ( delta radius ) ]
}
;

While we are able to simplify T ( 1 ) to T ( 2 ) ,
T ( 2 )
=
{
2 * logarithm ( delta frequency ) - 3 * logarithm ( delta radius )
}
/
2

And we have to correct our prefinal result about solving this equation
written above for delta frequency ( using T ( 2 ) ) , what results

2 * logarithm ( delta frequency ) =
logarithm [ ( delta radius ) exponent 3 ]
plus
2 * logarithm ( delta frequency )
minus
3 * logarithm ( delta radius )

And that is the way , we almost get stuck ...
Maybe our future will show new ways , while a
calculation of a minimal photon radius is in
progressive work and it seems to fit the Planck
Length as far as we have seen for now ...

On April 17th , we have found to a new , possible equation
describing frequency ( f ) of our Milky Way around the
Super Massive Center :

1 / frequency ( f ) squared
=
( distance of the SMC to Earth ) to the power of three
/
(
radius ( r ) of a photon at one spin per second
*
distance of the SMC to Earth
)
exponent 3
/
( 1,9878862577579345578272656386017 * 2 ) square
;

And we are going to see this calculation with exact values :

1 / frequency ( f ) squared
=
1,4575932846355137639737138060511e+126
/
(
v 2,3943600123792969381313194102613e-30
*
1,1338234969826428288348939717868e+42
=
2.714.781.642.271,2984282276923733951
)
exponent 3
/
( 1,9878862577579345578272656386017 * 2 ) square
;

1 / frequency ( f ) squared
=
1,4575932846355137639737138060511e+126
/
2,000804757149773958581513598263e+37
/
( 1,9878862577579345578272656386017 * 2 ) square
=
7,2850350811436166018816899844589e+88
/
( 1,9878862577579345578272656386017 * 2 ) square
;

7,2850350811436166018816899844589e+88
/
( 1,9878862577579345578272656386017 * 2 ) square
;

7,2850350811436166018816899844589e+88
/
15,806767095131381727979404318712
=
4,6088077576517649633713241776049e+87
;

And the delta to our former calculations , using
moon and the equation r exponent 3 = f squared
( 4,6051449040608704890918700231293e+87 )
is
1,0007953829178457614353994634483
;

We are glad to say that we could write down
about having calculated the exact age of our
Universe seen from Earth and we start right
ahead with this way to calculate :

1,1338234969826428288348939717868e+42     |   4,200150305 ... th root
( by the Antique Algorithm )
10.295.055.485,69688217271465357446     |
times
1,1338234969826428288348939717868e+42
=
1,1672775812423179386844781939422e+52     |   times 15

(
15 is because 7 + 8 ,
while 8 is the first integer in exponent 3 ,
1,200150305 ... th root of 8 is 5,655626722298043576373944664773 ;
5,655626722298043576373944664773     |   square
31,986113621971711713810688594697     |   third root of
3,1743428030945179949109986202232
as close to pi as possible ;
and 8 - 1 = 7 , while 7 is the third prime number ;
and 4,200150305 th root of 7 is
1,5893026900891086748995472590271     |   exponent 3
4,0143927114738695927478421555089 ,
what is as close to 2 square as possible by the Antique Algorithm .
The integer ' 15 ' is referred to as the ' Jules Julsky Value ' ,
and it is still unsure if we can calculate with it ...
)

1,750916371863476908026717290913(2)e+53     |   per V , the speed our Universe expands with

1,750916371863476908026717290913e+53
/
4,017177863209218599425380960825e+35
( calculated by ' c ' exponent 4,200150305 ... , provided by the Antique Approach )
=
435.857.318.616.386.951,41751426840418     |   per ( 3600 seconds * 24 * 365,256 )
13.811.258.107,719975834095174330931 years

We might serve with a solution for calculating the radius and
hence the density of the Super Massive Center , using the first
delta what is mentioned below :

Distance to our Earth is equal to
1,1338234969826428288348939717868e+42
meters
and the relative Age of our Universe ( seen from Earth ) is
13.811.258.107,719975834095174330931
years ;

13.811.258.107,719975834095174330931 years
times
[ ( 3600 seconds * 24 * 365,256 * light speed c ) squared = 89.508.361.728.822.451.951.262.224.511.140 ]
=
1,2362230866359314824696898922841e+42
and the delta to the radius
1,1338234969826428288348939717868e+42
is

1,0903135187494321621368310971449 ;
what suggests , that the squared entirety of the
distance , light has passed during this time is
approximately equal to the radius , while we
assume the slight delta to derive from a radius ,
since the Super Massive Center should own a
dimensional size and the horizon , where space
starts to convert into time should be responsible
for the delta ( time has passed ) per ( exact
distance from our Earth ' s Center and the
middlepoint of the Super Massive Center ) ...

The radius of the Center should to be ' x '

x ( = 1 )
per
1,0903135187494321621368310971449
=
1
/
(
1,1338234969826428288348939717868e+42
times
x
)

Recognizing the squared x and x set to 1 within
this equivalent , we might immediately think about to
solve this equivalent by the Antique Algorithm , which
results the most likely case of the actual radius of the
big and massive ' Bright Dark Center ' at this certain
distance from our Earth ...

The equivalent above solved for x results

x exponent 2
=
1,0903135187494321621368310971449
/
1,1338234969826428288348939717868e+42 ;

1 / x squared
=
1,0399059330045872888502034460198e+42 ;

1,0399059330045872888502034460198e+42     |   4,200150305 ... th root of
10.085.285.634,592177895737445040127
what should to be the actual radius of the Event Horizon ;
Calculating the volume results

4.296.879.924.977.050.208.969.743.799.405,8 cubical meters ;
and mass per volume ,
1,8629952550872468333656374107205e+50 kilogramms
per
4.296.879.924.977.050.208.969.743.799.405,8 cubical meters
ends up in an average density of
43.356.930.787.336.282.346,276267004055
kilogramms per cubical meter ;

way to calculate and since an average density might to be
nonsense we are going to move on with thinking about the
second delta , whereas this might pose the delta time :

We have calculated our Earth ' s Mass to
5.942.908.179.086.327.251.199.028,0842196
kilogramms by an exact value for G ;

1,8629952550872468333656374107205e+50
per
5.942.908.179.086.327.251.199.028,0842196
=
31.348.208.637.032.431.366.278.913,623042 ;
31.348.208.637.032.431.366.278.913,623042
/
13.811.258.107,719975834095174330931 years
=
2.269.757.642.101.406,9109318294926575 ;
2.269.757.642.101.406,9109318294926575
/
1 light year ( = 9.460.885.884.991.027,2 meters )
=
0,23990963105285986356333063345487     |   1 / x
4,16823616297283040348436613648325 ;
while this delta might show the delta of time passing
slower or faster due to the large mass of the Center ...

We have found , that our equations might fit exactly the age of our Universe :

1 Light Year ( 9.460.885.884.991.027,2 )
*
the exact age our Universe ( = 13.811.258.107,719975834095174330931 years )
=
130.666.736.885.295.803.244.583.186,77496
And the delta to the distance of the Super Massive Center
( 1,1338234969826428288348939717868e+42 meters )
is
8.677.215.977.146.164,7317841419193842 ;
The delta to 1 Light Year of this value is equal to
1,0903135187494321621368310971449
what poses the exact value we have been calculating the radius of
the Super Massive Center from ...

What we have seen is , that we have to multiply the age of our Universe ,
relative to our Earth , by one Light Year squared .
And the reason for this should to be that time slows down or increases by
its square regarding gravitational time dilation ...
(
E = time squared ;
)

Distance of the Super Massive Center from Earth
=
Age of our Universe relative to our Earth
*
1 Light Year squared
;

Finally , we have found that the circular passing of time , while time
accelerates and decelerates since the Big Bang , is in harmony with
the distance of the Super Massive Center , so that its radiation reaches
our Planet Earth ( from the past ) , and these particles have passed
throughout a longer period or duration of time compared to the ( past )
The equation for a circle is
radius squared = ( delta x ) squared plus ( delta y ) squared ;
And we are able to use this equation for our calculations with time and
the distance of the Super Massive Center ...

For this day we have come to new conclusions about the search for
extraterrestrial lifeforms , how so ever these might take form ...

Knowing an exact value for the radius by the Antique Approach , what
should result a sphere around our Earth , we can search a circle , the
intersection space of a sphere , known by the Antique Approach , and
the distance from the Super Massive Center of our Universe from Earth ...

In the following , our Earth represents the whole of our Universe ,
whereas we might put a ' little ' questionmark behind this claim .

Earth ' s Volume ( including our Atmosphere ) should be
1.300.310.443.732.228.506.213,8511374762 cubic meters ,
calculated with a radius of 6.771.000 meters ...

On our Earth , there live about
7,837 * 10 exponent 9 men ;
( while this has changed during a relative short period of time )
and we assume a men to own about 1 cubical meter of volume ,
what is a rough estimation , we are going to see the volume of
ants in this extrapolation at the lower part of the calculations ...

1.300.310.443.732.228.506.213,8511374762
per
7,837 * 10 exponent 9
is equal to
165.919.413.516,93613706952292171446
cubical meters per human living , and for now ,
we are going to see the cuberoot of this value ,
which is
5.494,9751739652025379295651715999     |   exponent 4,200150305
5.109.968.477.391.938,7323048815303903     |   per ( 9,461 * 10 exponent 15 = 1 light year )
0,54010870704914266275286772332632 light years of radius around earth
for the most likely distance to meet another human life within our Universe ...
This seems not be very likely at all ? So we move on with furtherleading thoughts :

With most lifes on our Earth , threadworms ( these are estimated to 4,4 * 10 exponent 20 livings )
it seems to work out by the same ratio , Earth volume per count of livings , but with an important difference :
We are going to set a threadworm to one cubical meter ( = One ' Unit of Life ' ) , so that we have to
expand our Earth ' s Volume by the factor 1.000.000.000 , because we assume a threadworm to own a
volume of approximately 1 cubical millimeter :
1.300.310.443.732.228.506.213,8511374762 * 1.000.000.000 ;
1.300.310.443.732.228.506.213.851.137.476,2
per
440.000.000.000.000.000.000
=
2.955.251.008,4823375141223889488095 ;
2.955.251.008,4823375141223889488095     |   cubic root
1.435,042592993689057602450857844     |   exponent 4,200150305 ...
18.167.978.884.316,280762229433405606 meters to find the next threadworm ,
which is about 0,00192 ... light years ...
This seems to make much more sense at times .
While threadworms even might represent another life within our Universe ...

(
An interesting calculation we have found is the ratio of
( threadworms per cubical meter )
per
( human per cubical meter ) ,
165.919.413.516,93613706952292171446
per
2.955.251.008,4823375141223889488095
resulting
56,143932627280847262983284420061
the cubical root is
3,8291373376604494993549260790957
times the average distance to see the next threadworm on earth
( 1.435,042592993689057602450857844 )
5.494,9751739652025379295651716     |   exponent 4,200150305
5.109.968.477.391.938,7323048815303906     |   per ( 9,461 * 10 exponent 15 = 1 light year )
0,54010870704914266275286772332636
what is the same value like calculating with men ...
)

Let us see more by calculating with ants , whereas we deal with a count of
10 exponent 16 lifes , and a volume of two cubical millimeters , firstly
we will see the expanding factor for ants to measure one cubical meter :

1.000.000.000 per two = 500.000.000 ;
1.300.310.443.732.228.506.213,8511374762 * 500.000.000 =
650.155.221.866.114.253.106.925.568.738,1     |   per 10 exponent 16
65.015.522.186.611,42531069255687381     |   cuberoot
40.210,45786734007614247444259332     |   exponent 4,200150305
21.823.074.346.793.330.544,23004077987     |   per light year
2.306,6350646647638245671747996904 light years to meet the next ant ;

So let us see the concluded recognition now :
We just might calculate with threadworms
( plus all the other lifes on our Earth , which
should not matter much for the value ) as
' one Life Unit ' to be set to one cubical meter ,
the number of threadworms is very close to an
estimated maximum value for the count of all
lifes on Earth with the exception Virus and Bacteria ...

Using the ratio with 10 * 10 exponent 12 bacteria per
human and a minimum size of 10 exponent -7 meters of a
bacterium life returns similar values like ' using threadworms ' .

An interesting thing we have found too , is the ratio
of
1.087.000.000 cubical kilometres of earth
( our planet ' s earth proportion )
/
1.400.000 cubical kilometres of water
( our planets water portion ) =
776,42857142857142857142857142857     |   exponent 4,200150305
1.376.767.901.161,5978017573373466257 cubical kilometers
and calculating the radius ( by Volume = 4 / 3 * pi * radius exponent 3 )
results a radius of 6.901,1908988372582807186889547443 kilometers ,
what is a value very close to our Earth ' s radius ;
We have tried to calculate the most likely distance of extraterrestrial water sources ,
whereas we see a potential to find other lifes by calculating the most likely distance
of water resources also and we are going to give it a trial to the best by this way :

Our Earth ' s Surface is covered by approximately
149 * 10 exponent 12 square meters of land .
We are going to extract the squareroot of this value , what results
12.206.555,615733702951897855256623     |   per two
6.103.277,8078668514759489276283115     |   exponent 4,200150305 ...
31.650.828.736.235.635.601.765.601.628,177 ;
now , we are going to extract the squareroot again , because
we have expanded meters to square meters by the Antique Algorithm ,
if we would have grown square meters by this special Algorithm , our
result would be cubical meters , because of ' extruding ' square meters
to a volume , and we have reduced by one dimension ...
31.650.828.736.235.635.601.765.601.628,177     |   squareroot
177.906.797.892.142,49022157196942124     |   per ( 9,461 * 10 exponent 15 = 1 light year )
=
0,01880422766009327663265743255694 light years to find the next water source
in comparison to
0,00192 ... light years to find the next life or just threadworm ,
what would make sense if we regard our Solarsystem to be the unit 1 ,
with our Earth and Enceladus , a satellite of Saturn covered with ice ...

For now , it seems that we have been able to determine the
maximum of electromagnetic radiation of the core of our
Milky Way what enables us to calculate the exact distance
from Earth ...

which is 10 times 4,200150305 ...
We assume that the measured frequency on Earth is
10 exponent 20,5 ( it should work out well with other
measured frequencies , too )
42,00150305 minus 20,5 times 2
is equal to
1,00150305     |   per 2
( because the delta frequency gets less by its inverse square )
0,500751525     |   plus 20,5
21,000751525     |   minus logarithm of 1,200150305 ...
( the minimum expansion by the Antique Algorithm )
21,000751525 minus 0,07923563983459043127267726500188
20,921515885165409568727322734998
( The original or source frequency , which should be pretty much
the same within most of Galaxies or even each of these )

We are going to see how to calculate the source frequency of the
Super Massive Center of our Universe too , which works with some
tiny differences :

The logarithm of the measured frequency which arrives on Earth is
23,476820702927927554392266208226     |   times 4
93,907282811711710217569064832904     |   minus 4,200150305 ... * 2 * 10
93,907282811711710217569064832904 - 84,0030061
9,904276711711710217569064832904     |   per two
4,952138355855855108784532416452     |   plus 23,476820702927927554392266208226
28,428959058783782663176798624678     |   minus logarithm of 23,476820702927927554392266208226
28,428959058783782663176798624678 minus 1,370639283177658833272870481247
27,058319775606123829903928143431
in comparison to the present approach written above , which delivers
27,054946002045772260836899614114

I would like to wish you to have a nice and colourful time during this Advent   &   Maybe you will like to visit   Peta   again !

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